Sol. As here,

ω 0 = = = 10 4 rad/s

so ω = ω 0 – ω 0 = ω 0 = 9 × 10 3 rad/s

and hence, X L = ω L = 9 × 10 3 × 10 –2 = 90 Ω ,

X C = = = 111.11 Ω

So, X = X L – X C = 90 – 111.11 = – 21.11 Ω

and hence,

Z = = ,

i.e., Z = = 21.32 Ω

and as here v = 15 cos ω t, i.e., V M = 15 V

I M = = = 0.704 A

The average power dissipated,

P av. = V rms I rms cos φ = (I rms × Z) × I rms ×

i.e., P av. = R =

so, P av. = × (0.704) 2 × 3 = 0.074 W

Now as f = = cycle/s

so, = =

i.e., = 5.16 × 10 –4 J/cycle